13. ELECTRON

 

Electron - first experimentally detected fundamental particle. By witty experiments the scientists have defined electric charge of an electron and its mass and it considerably have outmarch the theorists, which one can not count up the sizes of an electron, its own angular momentum, and about a construction of this particle the theorists do not stammer at all. The main reason: on a going into the microcosmos hangs the huge lock Indeterminacy relation of the Heisenberg, which one does not resolve not only precise calculations, but even the suppositions about a construction and properties of elementary particles. New physics ignores fabrications of orthodoxes, therefore bull can do that is not allowed to Jove. Earlier we have found, that the own moment of an electron is peer:

a (1), where a - fine structure constant, and �- angular momentum of an electron on coils of a screw trajectory. Here I address. attention of the reader, that official physics considers angular momentum of an electron equal /2 and on it all modern physics is built. The Nay that it gives an error angular momentum of an electron, it does not know yet that it is a moment at screw motion, and considers as its own angular momentum. At such moment the electron should be gyrated in 300 times faster than speed of light and that itself to not flog, the orthodoxes have called its �spin�, as though from it something will change in their heads. The reader will rummaged the literature on this problem and will not discover sensible explanation of an orthodox fabrication - �spin�. Let's presume, that the electron consists of two any components moved on a circular orbit with speed of light (so all elementary particles are arranged, only number of components variously). Then we can record an own angular momentum of one of components:

a/2=m_ecr_e/2 (2), where m_e/2 - mass of one of components, c - speed of light, r_e - radius of an electron. If from (2) we shall express radius of an electron and we shall substitute tabulared values of constants, we shall receive: r_e=2.8179×10^-13 cm. Tabulared value �of classic radius of an electron� r_e=2.81785×10^-13 cm.

Now we shall conduct one imaginary experiment. Such experiment is good by that to it spit on indeterminacy relation and on influence of �instrument� on measured parameter of a microparticle. Step-by-step we shall accelerate an electron and we shall look, that from this will be received. Let's record angular momentum of an electron on a screw trajectory:

=m_eVR (3), where V - forward speed of an electron, equal tangential velocity, R - radius of an coil of a trajectory. Always we shall remember, that the law of conservation of angular momentum requires, that the product VR should remain to a constant, i.e. at increase of speed, radius of a screw trajectory decreases. Let's look, what is necessary speed, that this radius has become peer to radius of orbit of the Bohr. It appears, that this speed in 137 times is less than speed of light. And if to speed up an electron up to speed of light? Then pursuant to the formula (3) radius of a screw trajectory will become equal 386.134×10^-13 cm. This value official physics calls �a Compton wavelength of an electron�, but is useless to ask, what physical sense of this concept. Further electron is useless to accelerate, it can not move faster than light, and the formula (3) obtains a kind:

=m_eRc (4). Now law of conservation of angular momentum requires, that at decreasing radius of a screw trajectory the particle mass should be augmented. It also will originate at increase of energy of an electron (speed it is not augmented any more). Let's presume now, that in this ultra relativistic area we have given so much to energy to an electron, that radius of its screw trajectory has coincided with classic radius of the� electron:

=m_er_ec (5), then from (5) it is possible to find electronic mass in these conditions: it will be increased in 137.03596 times and in an energy equivalent will become equal 70.0252673 MeV. As the particles in a free condition have a moment , apparently, that the �exited� quantum condition of the given particle will be aliquot to this value. Therefore, the energy levels of elementary particles will be aliquot 70.025 MeV or half of this value, if the orbital angular momentum any of a component is peer /2. In spite of the fact that masses of elementary particles the most miscellaneous of (5) follows, that radius them, approximately, identical. The details can be learned from the following chapter.